“Separate first, always”
Which method to try
If the equation can be written with all the y terms on one side and all the x terms on the other, the rest is just two integrations.
Mathematics, Class 11 and 12 · Gujarat Board, CBSE, GUJCET and JEE
A short, highly patterned chapter. Identify the type, apply its method, and the marks follow. Variable separable and linear equations between them cover the great majority of what is asked.
13 formulas, 3 memory hooks, and the 5 mistakes that cost the most marks.
| What | Formula | Symbols and notes |
|---|---|---|
| Order | the highest derivative present | y'' gives order 2 |
| Degree | the power of the highest derivative, once free of radicals | not defined if it cannot be made polynomial |
| General solution | contains as many arbitrary constants as the order | a first order equation has one |
| Particular solution | the constants fixed by given conditions | substitute the initial values |
| What | Formula | Symbols and notes |
|---|---|---|
| Variable separable | write as f(y)dy = g(x)dx, then integrate both sides | the first thing to try |
| Homogeneous | substitute y = vx, so dy/dx = v + x dv/dx | when every term has the same total degree |
| Linear in y | dy/dx + Py = Q, with P and Q functions of x | the standard linear form |
| Integrating factor | IF = e∫P dx | multiply through by it |
| Linear solution | y × IF = ∫(Q × IF)dx + c | the result worth memorising |
| Linear in x | dx/dy + Px = Q | the same method with the roles swapped |
| What | Formula | Symbols and notes |
|---|---|---|
| From a family of curves | differentiate as many times as there are constants | then eliminate them |
| Growth and decay | dy/dt = ky gives y = y₀ekt | k positive for growth, negative for decay |
| Newton's law of cooling | dT/dt = −k(T − T₀) | the same shape of equation |
Taught by Darshit Bhatt, founder and lead faculty at Darshit Sir Institute. Instrumentation and Control engineer, with a master's degree and a chartered degree, teaching in Paldi, Ahmedabad since 2006.
Memory hooks
“Separate first, always”
Which method to try
If the equation can be written with all the y terms on one side and all the x terms on the other, the rest is just two integrations.
“e to the integral of P”
The integrating factor
Get the equation into dy/dx + Py = Q form first, with the coefficient of dy/dx equal to one, then IF = e∫P dx.
“One constant per order”
How many constants to expect
A first order equation has one arbitrary constant in its general solution, a second order two. Use it as a check.
Where marks go
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